✔ 最佳答案
1. This is a Young double slit experiment with the two waves were in phase initially.
In this circumstance, you will have the central maximum (constructive interference in the centre), then there will be adjacent minimum and maximum seen on the screen.
If now a thin glass piece is added and the two waves are 180* out of phase, then you will see a dark fringe in the centre since destructive interference occurs there (the path difference is half wavelength), and the bright and dark fringes patterns will be interchanged correspondingly.
2. Grating separation, d = 0.01 / 6000 = 1 / 600 000 m
Wavelength, s = 633 X 10^-9 m
By ms = dsin@
m = dsin@ / s <= d / s (Since sin@ <= 1)
m <= (1 / 600 000) / (633 X 10^-9)
m <= 2.63
m is the highest integer not greater than 2.63
So, m = 2
Therefore, the highest spectral order that can be seen is 2.