g是向下的加速度(對邊)
a是沿斜面滑下的加速度(斜邊)
sinθ = 對邊/斜邊
= g/a
g = a sinθ ?
咁點解 a = g sinθ？
我的概念錯在哪？
中四中五力學疑問 a = g sinθ?(中文答 plz)
2009-02-21 8:42 pm
回答 (2)
2009-02-21 10:14 pm
✔ 最佳答案
The answer is as follows:圖片參考：http://i320.photobucket.com/albums/nn347/old-master/900221_2.jpg?t=1235196832
2009-02-22 12:49 am
sinθ = 對邊/斜邊
= g/a <---- this is wrong, g is NOT the "opposide side"
The vector triangle of g and its two resolved components is NOT the same as the geometrical figure of the inclined plane.
= g/a <---- this is wrong, g is NOT the "opposide side"
The vector triangle of g and its two resolved components is NOT the same as the geometrical figure of the inclined plane.
收錄日期: 2021-04-29 17:27:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090221000051KK00756