Solve 4(x - 3) - 2(x - 1) > 0.?

4x - 12 - 2x + 2 > 0 <=> 2x -10 > 0 <=> 2x > 10 <=> x > 5

1) Distribute
4x-12-2x+2 >0

2) Simplify
2x-10>0

3) Solve through algebra

a) Add 10 from both sides
2x>10

b) Divide both sides by 2
x>5

Answer: X| x>5

Distribute first:
4x-12-2x+2>0

Add like terms:
2x-10>0

Add 10 to both sides:
2x>10

Divide both sides by 2:
x>5 (the second choice)

2x > 10 ---> x > 5

Open all the brackets 4x^2 + 4x + 1 -6x -3 -8x^2 +2 =0 Collect like terms together -4x^2 - 2x = 0 This is the sames as 4x^2 + 2x = 0 factorize with 2x Gives 2x(2x +1) = 0 So x = 0 or -1/2

4x - 12 - 2x + 2 > 0
2x - 10 > 0
2x > 10
x > 5
{x | x > 5}

4(x - 3) - 2(x - 1) > 0
4*x - 4*3 - 2*x + 2*1 > 0
4x - 12 - 2x + 2 > 0
4x - 2x > 12 - 2
2x > 10
x > 10/2
x > 5

4x - 12 - 2x + 2 > 0 <=>

2x -10 > 0 <=>

2x > 10 <=>

x > 5

*=squared

(4x-12)-(2x-2) >0

4x-2x=2x
4x - -2=4x+2
-12 - 2x=-12+ -2x
-12--2=-12+2=-10

combine like terms:

2x+4x=6x-2x=4x
-12+2-10=-10 +10=0
x=4

4x-12-2x+2>0
2x-10>0
2x>10
x>5

answer: x>5

Im 100% sure! :)