factor x^3 + 8 mathematics?
回答 (4)
2009-02-18 4:33 pm
✔ 最佳答案
Factorize x^3 + 8x^3 = -8 (making x the subject of the formula)
Take the cube root of both sides
we have, cube root of x^3 = cube root of -8
x = -2.
參考: No source!
2009-02-18 11:31 pm
a^3 + b^3
( a + b ) ( a^2 - ab + b^2 )
x^3 + 8
= x^3 + 2^3
= (x + 2) (x^2 - x*2 + 2^2)
= (x + 2) (x^2 - 2x + 4)
( a + b ) ( a^2 - ab + b^2 )
x^3 + 8
= x^3 + 2^3
= (x + 2) (x^2 - x*2 + 2^2)
= (x + 2) (x^2 - 2x + 4)
2009-02-18 11:29 pm
x^3 + 8
= x^3 + 2^3
Using formula x^3+y^2 = (x+y)(x^2 - xy + y^2), we get
x^3 + 2^3 = (x+2)(x^2 - x * 2 + 2^2)
= (x+2)(x^2 - 2x + 4)
Ans: (x+2)(x^2 - 2x + 4)
= x^3 + 2^3
Using formula x^3+y^2 = (x+y)(x^2 - xy + y^2), we get
x^3 + 2^3 = (x+2)(x^2 - x * 2 + 2^2)
= (x+2)(x^2 - 2x + 4)
Ans: (x+2)(x^2 - 2x + 4)
2009-02-18 11:29 pm
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
x^3 + 8
= x^3 + 2^3
= (x + 2)(x^2 - x*2 + 2^2)
= (x + 2)(x^2 - 2x + 4)
x^3 + 8
= x^3 + 2^3
= (x + 2)(x^2 - x*2 + 2^2)
= (x + 2)(x^2 - 2x + 4)
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