solve for x: x-12(2x-4)=6?

simpifly first (remember multiplication trumps addition):
x-24x+48 = 6 and collect terms (variables on left, constants on right of the equals)
-23x = - 42 solve for x
x = 42/23
viola!

(x/4) + 6 = x - 3 (x/4)=x-9 x=4x-36 3x=36 x=12 EDIT: Mamamia is faulty. whilst she took the x to the otherside, she forgot to get rid of the adverse sign beside the 36.

x - 24 x + 48 = 6
42 = 23 x
x = 42 / 23

x - 12(2x - 4) = 6
x - 12*2x + 12*4 - 6 = 0
x - 24x + 48 - 6 = 0
-23x + 42 = 0
-23x = -42
x = -42/-23
x = 42/23

x-12(2x-4)=6
x-24x+48=6
-23x=6-48
-23x = -42
x=42/23

x-12(2x-4)=6
x-24x-48=6
-23x - 48=6
-23x=54
x=-54/23=2.34

x - 24x + 48 = 6

-23x + 48 = 6

Subtract 48

-23x + 48 - 48 = 6 - 48

-23x = -42

Divide by -23

-23x/-23 = x = -42/-23 = 42/23

3x-12(2)
x=24/3=8
so the question is wrong,it should be 8 instead of 6

first you have to distribute the -12.
x-24x+48=6
Then you would combine all the like terms
-23x=-42
Then divide by -23
x=42/23
(the answer would be positive because both the numbers you are dividing are negative.)
X=42/23

Hope this Helps : )

x - 24x + 48 = 6

-23x = -42

x = 42/23