how do you find the slope? 6x+4y=16?

y = mx + c (m = slope)

6x + 4y = 16
4y = -6x + 16
y = (-6x)/4 + 16/4
y = (-3x)/2 + 4
y = -3/2(x) + 4

∴ slope = -3/2

To find the slope of a line, put it in slope-intercept form. That means to solve the equation for *y*. It will have a form of y = mx + b.

m = slope
b = y-intercept

Let's do your equation
6x + 4y = 16

Subtract 6x from both sides to take it over to the right side
6x - 6x + 4y = 16 - 6x

you get:
4y = 16 - 6x

Now, divide both sides by 4 to take it over to the right side
4/4 y = 16/4 - 6/4x

You get: y = 4 - 6/4x

Since 6/4 reduces, divide it by 2 on top and bottom and you get:

y = 4 - 3/2 x

Now, the slope is the number (or coefficient) in front of *x*

slope = -3/2

I hope this is helpful to you
:o)
dr

6x+4y=16
4y=-6x+16
y=-6/4x+4 or -3/2x+4

therefore the slope is m=-3/2 answer//

slope= -(co-efficient of X)/(co-efficient of Y)

ie -(6/4)

First you must get the equation in to standard form (y = mx + b). In simple terms, solve for y.

This will give you y = (-3/2)(x) + 4

When in standard form, m is your slope and b is your y-intercept. Therefore, your slope (the number attached to the x) is -3/2 and it intercepts the y-axis at (0,4).

This will help for your other question, as well.

You need to put it in point slope form, of y=mx+b
4y=-6x+16 Divide by 4 on both sides
y=(-6/4)x+4 Simplify
Slope = -3/2