How do you factorise "x(x+2)-x-2"?
回答 (8)
2009-02-16 10:22 am
✔ 最佳答案
(x+2)(x-1) 
2009-02-16 7:14 pm
x (x + 2) - (x + 2)
(x + 2)(x - 1)
(x + 2)(x - 1)
2009-02-16 6:23 pm
x(x + 2) - x - 2
= x(x + 2) - (x + 2)
= x(x + 2) - 1(x + 2)
= (x + 2)(x - 1)
= x(x + 2) - (x + 2)
= x(x + 2) - 1(x + 2)
= (x + 2)(x - 1)
2009-02-16 6:20 pm
x(x+2)-x-2
=x(x+2)-(x+2)
=(x-1)(x+2) answer//
=x(x+2)-(x+2)
=(x-1)(x+2) answer//
2009-02-16 6:19 pm
distribute the x to the (x+2), so you now get
x^2+2x-x-2
then simplify by combining the x's, so you now get
x^2-x-2
you know when you now factor the equation you need two seperate equations, each starting with a postive x (so when mulitplied you get your positive x squared) and two integers that when added together equal negative one and when multiplied equal negative two
(x-2) (x+1)
is the final answer, you can check it by FOILing it out and if you get the original equation you know you did it right!
x^2+2x-x-2
then simplify by combining the x's, so you now get
x^2-x-2
you know when you now factor the equation you need two seperate equations, each starting with a postive x (so when mulitplied you get your positive x squared) and two integers that when added together equal negative one and when multiplied equal negative two
(x-2) (x+1)
is the final answer, you can check it by FOILing it out and if you get the original equation you know you did it right!
2009-02-16 6:18 pm
First you expand out everything:
x(x+2) - x - 2
= x^2 + 2x - x - 2
Then add/subtract the values with the same coefficient:
= x^2 + x - 2
And finally you factorize everything by cross multiplying:
= (x+2)(x-1)
x(x+2) - x - 2
= x^2 + 2x - x - 2
Then add/subtract the values with the same coefficient:
= x^2 + x - 2
And finally you factorize everything by cross multiplying:
= (x+2)(x-1)
2009-02-16 6:17 pm
x(x + 2) - x - 2 = 0
x² + 2x - x - 2 = 0
x² + x = 2
x² + 1/2x = 2 + (1/2)²
x² + 1/2x = 8/4 + 1/4
(x + 1/2)² = 9/4
x + 1/2 = 3/2
Factors:
= x + 1/2 + 3/2, = x + 4/2, = x + 2
= x + 1/2 - 3/2, = x - 2/2, = x - 1
Answer: (x + 2)(x - 1) are the factors.
x² + 2x - x - 2 = 0
x² + x = 2
x² + 1/2x = 2 + (1/2)²
x² + 1/2x = 8/4 + 1/4
(x + 1/2)² = 9/4
x + 1/2 = 3/2
Factors:
= x + 1/2 + 3/2, = x + 4/2, = x + 2
= x + 1/2 - 3/2, = x - 2/2, = x - 1
Answer: (x + 2)(x - 1) are the factors.
2009-02-16 6:15 pm
x(x+2)-x-2 = x(x+2) - 1(x+2) = (x+2)(x-1)
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