How do you factorise "x(x+2)-x-2"?

(x+2)(x-1)

x (x + 2) - (x + 2)
(x + 2)(x - 1)

x(x + 2) - x - 2
= x(x + 2) - (x + 2)
= x(x + 2) - 1(x + 2)
= (x + 2)(x - 1)

x(x+2)-x-2
=x(x+2)-(x+2)
=(x-1)(x+2) answer//

distribute the x to the (x+2), so you now get

x^2+2x-x-2

then simplify by combining the x's, so you now get

x^2-x-2

you know when you now factor the equation you need two seperate equations, each starting with a postive x (so when mulitplied you get your positive x squared) and two integers that when added together equal negative one and when multiplied equal negative two

(x-2) (x+1)

is the final answer, you can check it by FOILing it out and if you get the original equation you know you did it right!

First you expand out everything:

x(x+2) - x - 2
= x^2 + 2x - x - 2

Then add/subtract the values with the same coefficient:

= x^2 + x - 2

And finally you factorize everything by cross multiplying:

= (x+2)(x-1)

x(x + 2) - x - 2 = 0
x² + 2x - x - 2 = 0
x² + x = 2
x² + 1/2x = 2 + (1/2)²
x² + 1/2x = 8/4 + 1/4
(x + 1/2)² = 9/4
x + 1/2 = 3/2

Factors:
= x + 1/2 + 3/2, = x + 4/2, = x + 2
= x + 1/2 - 3/2, = x - 2/2, = x - 1

Answer: (x + 2)(x - 1) are the factors.

x(x+2)-x-2 = x(x+2) - 1(x+2) = (x+2)(x-1)