Algebra I Help: (x+1)^-2 (x+1)^3?
2009-02-16 10:06 am
i know it's easy, but i want to make sure i got it right...work and answer please
回答 (4)
2009-02-16 10:15 am
✔ 最佳答案
(x+1)^-2(x+1)^3...(x+1)^3
=------------
...(x+1)^2
=x+1 answer//
2009-02-16 6:29 pm
(x + 1)^(-2) * (x + 1)^3
= (x + 1)^(-2 + 3)
= (x + 1)^(1)
= x + 1
= (x + 1)^(-2 + 3)
= (x + 1)^(1)
= x + 1
2009-02-16 6:11 pm
This equation is multiplying the ^-2 and ^3
when multiplying indicies, you add the numbers together. 3-2 = 1. Anything to the power of 1 is itself again. so, the answer is x+1
way to show it algebraically is:
(x+1)^-2 * (x+1)^3 = (x+1)^(-2+3) = (x+1)^1 = x+1
when multiplying indicies, you add the numbers together. 3-2 = 1. Anything to the power of 1 is itself again. so, the answer is x+1
way to show it algebraically is:
(x+1)^-2 * (x+1)^3 = (x+1)^(-2+3) = (x+1)^1 = x+1
2009-02-16 6:20 pm
My answer is:
6x^4+18x^2+18x
6x^4+18x^2+18x
收錄日期: 2021-05-01 12:01:54
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