AL Physics Electric Potential

7. Please follow the following link

http://i182.photobucket.com/albums/x4/A_Hepburn_1990/physicsworld10Feb151703.jpg



8.a. Average electric field, E

= V / d

= (2100 - 1900) / (0.1)

= 2000 Vm^-1

b.i. By the law of conservation of energy,

Loss of E.P.E. = Gain of K.E.

qV = 1/2 mv^2

(2 X 10^-3)(2100 - 1900) = 1/2 (0.020)v^2

Velocity, v = 6.32 ms^-1

ii. By F = qE

F = (2 X 10^-3)(2000) = 4N

By Newton's 2nd law of motion,

F = ma

4 = (0.020)a

Acceleration, a = 200 ms^-2

By equation of motion,

v^2 = u^2 + 2as

v^2 = 0 + 2(200)(0.1)

Velocity, v = 6.32 ms^-1