SHM and Fluid

2009-02-15 4:50 pm
A plastic cylinder of height 2h and cross-sectional area A floats in equilibrium in a fluid of density p in such a way that the bottom of the cylinder is a distance h below surface of the fluid. This situation is shown in Figure (a), where the x-axis has been chosen to point vertically downwards.A plastic cylinder of height 2h and cross-sectional area A floats in equilibrium in a fluid of density p in such a way that the bottom of the cylinder is a distance h below surface of the fluid. This situation is shown in Figure (a), where the x-axis has been chosen to point vertically downwards.


(a) Derive an expression in terms of known quantities and g for the force that must be applied to the top of the cylinder to depress it by a distance x, as shown in Figure (b).


(b) State why, when the cylinder is released, its vibrations will be simple harmonic, and write an expression for the force constant in terms of known quantities and g.


(c) What is the maximum theoretical value of x up to which the vibration will remain simple harmonic? Briefly explain your reasoning.


(You will need to use Archimedes's principle, which states that the upward force on an object in a fluid is equal in magnitude to the weight of the fluid displaced. When the cylinder is floating, the weight of the displaced fluid equals the weight of the cylinder. The force required to depress the cylinder below its equilibrium position will therefore be equal to the weight of the additional fluid displaced when the cylinder is depressed.)


The link is the figure reference
http://s675.photobucket.com/albums/vv116/mebo8866/?action=view&current=Image3.jpg

回答 (2)

2009-02-15 7:22 pm
✔ 最佳答案

圖片參考:http://i182.photobucket.com/albums/x4/A_Hepburn_1990/A_Hepburn01Feb151121.jpg?t=1234668133

AAAAAAAAAAAAAAAAAAAAAA


2009-02-16 14:15:44 補充:
Let m be the mass of the block.
mass = density X volume X gravitational field
So, m = p'A(2h)g

Now, F = ma
ma = mx"
p'A(2h)g = p'A(2h)g - pA(h + x)g (F is given by the difference in upthrust and the weight of the block)
p'A(2hg)x" = pAxg
參考: Myself~~~
2009-02-16 2:16 pm
Where is the m (mass) can be simplied ?

p'A(2h)gx"=pAxg


F=ma

ma=mx"

mx"=p'A(2h)g-pA(h+x)g

p'A(2h)gx"=pAxg (How does the formula form?)


收錄日期: 2021-04-25 16:23:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090215000051KK00403

檢視 Wayback Machine 備份