f.5PHY一問

2009-02-15 5:44 am
ken chan of height 1.8 m with his eye 1.74 m above the ground stands in front of a plane mirror . what is the minimum length of the mirror so that he can see his whole image.

要點計呀?
同埋幅圖要點畫呢=]
更新1:

我只係唔知如果做long question既時候,步驟要點寫 所以麻煩大家寫出詳細既步驟,thx=]

回答 (2)

2009-02-15 8:40 am
✔ 最佳答案
Draw the ray diagram as follows:
First draw the image of the man, which is at the same distance behind the mirror as the object (man) in front (say, d metres), with the same size as the object (1.8 m in height)
From the eyes of the man, construct two rays, one passess through the top of the mirror and end at the top of the man's image. The other passes through the bottom of the mirror and end at the feet of the man's image.
Now, you can see that the man'e eyes, the mirror and the image form two similar triangles, with heights (of triangles) equal to d and 2d respectively (the height of triangle is measured from the eye to the mirror and image).
Hence, d/2d = h/1.8
where h is the height of mirror
i.e. h = 1.8/2 m = 0.9 m
Since in the ray diagram, the rays pass through the top and bottom of the mirror, the height of 0.9 m so calculated is the mimium height.
2009-02-15 5:47 am
人高度 1.8m

眼 1.74m

咁鏡要 1.74m + [(1.8m - 1.74m) / 2] <-- law of reflection

= 1.74m + 0.06m / 2

= 1.77m

2009-02-14 21:49:23 補充:
計漏野 @@

咁鏡要 [1.74m / 2] + [(1.8m - 1.74m) / 2] <-- law of reflection

= 0.87m + 0.03m

= 0.9m


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