6-7x-20x^2 factorized?

(2 - 5x)(3 + 4x)

anvil ltd.

6-7x-20x^2
20x^2 +7x -6
20(x^2 +7/20x -3/10)
20(x + 3/4)(x - 2/5)

- (20x² + 7x - 6)
- (5x - 2) (4x + 3)
(2 - 5x) (4x + 3)

6 - 7x - 20x^2
= -20x^2 - 7x + 6
= -(20x^2 + 7x - 6)
= -(20x^2 + 15x - 8x - 6)
= -[(20x^2 + 15x) - (8x + 6)]
= -[5x(4x + 3) - 2(4x + 3)]
= -(4x + 3)(5x - 2)

First, let's take out a -1 to make the x^2 positive:
-1(20x^2 + 7x - 6)

-1(5x - 2)(4x + 3)

FOIL
First: 5x * 4x = 20x^2
Outer:5x * 3 = 15x
Inner: -2 * 4x = -8x
Last: -2 * 3 = -6

Combine the Outer and Innter: 15x - 8x = 7x

20x^2 + 7x - 6

Answer: -1(5x - 2)(4x + 3)

impossible