Solve
3(2^(x+1)) - (2^(x-1)) = 276
Is it necessary to use 'log'?
Maths -- F.2 Integral Indices
2009-02-13 4:36 am
回答 (2)
2009-02-13 4:51 am
✔ 最佳答案
you must use log to solve this equationthe solution is as follows :
2^(x-1) [3*2^2-1] = 276
2^(x-1)(12-1)=276
2^(x-1)(11)=276
2^(x-1)=276/11
log2^(x-1)=log276/11
(x-1)log2=log276/11
x-1=log(276/11)/log2
x=log(276/11)/log2 + 1
I hope this can help you
參考: ME
2009-02-13 8:23 am
3(2x+1) - (2x+1) = 276
2(2x+1)=276
(2x+1)=138
2(2x)=138
圖片參考：http://f.imagehost.org/0489/ScreenHunter_01_Feb_13_00_20.gif
2(2x+1)=276
(2x+1)=138
2(2x)=138
圖片參考：http://f.imagehost.org/0489/ScreenHunter_01_Feb_13_00_20.gif
收錄日期: 2021-04-23 20:38:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090212000051KK01634