2√45
--------
7√80
divide and simplfy the following?
2009-02-11 2:25 pm
回答 (5)
2009-02-11 2:36 pm
✔ 最佳答案
(2√45)/(7√80)= [2√(3^2 * 5)]/[7√(4^2 * 5)]
= [2(3)√5]/[7(4)√5]
= (6√5)/(28√5)
= 6/28
= 3/14
2009-02-11 10:41 pm
2â45....2â(9*5)......6â5
--------=-------------=-----------=6/28 0r 3/14 answer
7â80....7â(16*5)....28â5
--------=-------------=-----------=6/28 0r 3/14 answer
7â80....7â(16*5)....28â5
2009-02-11 10:40 pm
2â45 = 2â(3*3*5) = 2*3â5..............i
7â80 = 7â(2*2*2*2*5) = 7*2*2 â5 = 7*4 â5 .........ii
On dividing i and ii
(2*3â5)/(7*4 â5) = 3/14
Answer 3/14
7â80 = 7â(2*2*2*2*5) = 7*2*2 â5 = 7*4 â5 .........ii
On dividing i and ii
(2*3â5)/(7*4 â5) = 3/14
Answer 3/14
2009-02-11 10:40 pm
2 x 3rt.5
----------
7 x 4rt.5
3
------
7 x 2
3
----
14
0.21428571...
----------
7 x 4rt.5
3
------
7 x 2
3
----
14
0.21428571...
2009-02-11 10:37 pm
2â45 = 6â5
7â80 = 28â5
6â5 / 28â5 = 6/28 = 3/14
7â80 = 28â5
6â5 / 28â5 = 6/28 = 3/14
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