中4math題..

2009-02-12 5:03 am
1) lf a=2-(1/b) , then b=?

2) lf a= (b-1)/(b-2), then b=?
a. 2a-1/a-1
b. 2a-1/a+1
c. 1/a-1
d. 1/a+1

3) lf the equation x^2- 4x+ k=1 has real root, then the ranga of values of k is..
a. k>4
b. k>=4
c. k>5
d. k>=5

4) find the ranga of values of k such that the quadratic equation x^2 + 2x- k= 2 has two distinct real roots.
a. k>-3
b. k>=-3
c. k>-1
d. k>=-1

5) the price of 6 oranges and 3 apples is $42 while the price of 8 oranges and 5apples is $60. find the price of an apple.
a. $3
b. $4
c. $5
d. $6

回答 (1)

2009-02-12 6:03 am
✔ 最佳答案
1)
a = 2 - (1/b)
(1/b) = 2 - a
b = 1/(2 - a)


2)
The answer is a.
a = (b - 1)/(b - 2)
a(b - 2) = b - 1
ab - 2a = b - 1
ab - b = 2a - 1
b(a - 1) = 2a - 1
b = (2a - 1)/(a - 1)


3)
There is no correct answer. The answer should be k ≤ 5.
x2 - 4x + k = 1 has real root.
x2 - 4x + (k - 1) = 0 has real root.
D = (-4)2 - 4(1)(k - 1) ≥ 0
16 - 4k + 4 ≥ 0
20 - 4k ≥ 0
5 - k ≥ 0
-k ≥ -5
k ≤ 5

If the question changes to "no real root", the answer is c.
x2 - 4x + k = 1 has no real root.
x2 - 4x + (k - 1) = 0 has no real root.
D = (-4)2 - 4(1)(k - 1) < 0
16 - 4k + 4 < 0
20 - 4k < 0
5 - k < 0
-k < -5
k > 5


4)
The answer is a.
x2 + 2x - k = 2 has two distinct real roots
x2 + 2x - (k + 2) = 0 has two distinct real roots
D = (2)2 - 4(1)[-(k + 2)] > 0
4 + 4k + 8 > 0
4k + 12 > 0
k + 3 > 0
k > -3


5)
The answer is b.
Let the price of an apple be $a, and that of an orange be $r.
6r + 3a = 42 ... (1)
8r + 5a = 60 ... (2)
4x(1): 24r + 12a = 168 ... (3)
3x(2): 24r + 15a = 180 ... (4)
(4)-(3): 3a = 12
a = 4
Price of an apple = $4
=


收錄日期: 2021-04-29 18:20:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090211000051KK01770

檢視 Wayback Machine 備份