please help with easy algebra problem.?

x = y + 3
2x - y = 5

2x - y = 5
2(y + 3) - y = 5
2*y + 2*3 - y = 5
2y + 6 - y = 5
2y - y = 5 - 6
y = -1

x = y + 3
x = -1 + 3
x = 2

∴ x = 2 , y = -1

2 (y + 3) - y = 5
2y + 6 - y = 5
y = - 1
x = 2

Rewrite the equations as

x - y = 3 -------- eq1
2x-y = 5 -------- eq2

Multiplying equation 2 with (-1) we get,

x - y = 3 --------> eq1
-2x+y = -5 --------> eq2
---------------------------------
-x = -2

hence x=2

substituting the value of x in eq1

2 - y = 3
=> -y = 1
=> y = -1

Ans: x=2 and y= -1

here is your ans:

put value of "x" ( from 1 eq ) in 2x-y=5 then it looks it this:

=> 2(y+3)-y=5
=> 2y+6-y=5
=> y= - 1

put value of y(y= -1 ) in 1st equation you get

=> x= 2

i think you are satisfied with this ....ok..

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2(y+3)-y=5
there you go now solve for y and then after that substitute y back into the first equation and you have your values for x and y.