physics(Rank-speed)

2009-02-09 8:50 am
Two cars travel on the parallel lanes of a two-lane road. The cars are at the same location at time , and move in such a way as to produce the velocity (relative to the ground) vs. time graph shown in the figure. (Intro 1 figure) On the graph, one vertical block is equivalent to one velocity unit.

Intro 1 figure:
http://session.masteringphysics.com/problemAsset/1011419/18/1011419.jpg


1...

Rank car #1’s speed relative to the ground at the lettered times (A through E).
Rank from largest to smallest. To rank items as equivalent, overlap them.

2...

Rank car #1’s speed relative to car #2 at the lettered times.
Rank from largest to smallest. To rank items as equivalent, overlap them.

3...

Rank the distance between the cars at the lettered times.
Rank from largest to smallest. To rank items as equivalent, overlap them.

回答 (2)

2009-02-09 12:12 pm
✔ 最佳答案
1. E > A > D > B > C (距離x-axis越遠就越快)
2. A > B > C > D > E (條線隔得越開越大)
3. da = 0 + 3t^2/20
db = -3t + 6t^2/20
so, distance = |db - da| = |3t - 3t^2/20|
A ==> d = 5.4
B ==> d = 9.6
C ==> d = 11.25
D ==> d = 13.65
E ==> d = 15
E > D > C > B > A

2009-02-09 13:18:13 補充:
因為兩件物件的相對速度, 即是把其中一方的速度減去另一方的速度
2009-02-09 1:13 pm
其實Q2 點解條線隔得越開越大???


收錄日期: 2021-04-15 21:11:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090209000051KK00081

檢視 Wayback Machine 備份