How do i factorise 2x^3(x+1)+3x^2(x+1)^2?
回答 (4)
2009-02-08 1:34 pm
✔ 最佳答案
2x^3(x + 1) + 3x^2(x + 1)^2= (x + 1)[2x^3 + 3x^2(x + 1)]
= (x + 1)[2x^3 + 3x^3 + 3x^2]
= x^2(x + 1)(2x + 3x + 3)
= x^2(x + 1)(5x + 3)
2009-02-08 1:11 pm
x^2(x+1)(2x 3(x+1))
=x^2(x+1)(5x+3)
=x^2(x+1)(5x+3)
2009-02-08 1:03 pm
To factor 2x^3(x+1)+3x^2(x+1)^2, first take out the (x+1) term, then x^2
2x^3(x+1)+3x^2(x+1)^2 = (x+1)(2x^3 +(3x^2)(x+1)) =
(x + 1)(x^2)(2x+3x + 3) = (x^2)(x+1)(5x+3)
2x^3(x+1)+3x^2(x+1)^2 = (x+1)(2x^3 +(3x^2)(x+1)) =
(x + 1)(x^2)(2x+3x + 3) = (x^2)(x+1)(5x+3)
2009-02-08 1:02 pm
x(x+1)(5x^2+3)
收錄日期: 2021-05-01 11:59:34
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