How do i factorise 2x^3(x+1)+3x^2(x+1)^2?

2x^3(x + 1) + 3x^2(x + 1)^2
= (x + 1)[2x^3 + 3x^2(x + 1)]
= (x + 1)[2x^3 + 3x^3 + 3x^2]
= x^2(x + 1)(2x + 3x + 3)
= x^2(x + 1)(5x + 3)

x^2(x+1)(2x 3(x+1))
=x^2(x+1)(5x+3)

To factor 2x^3(x+1)+3x^2(x+1)^2, first take out the (x+1) term, then x^2

2x^3(x+1)+3x^2(x+1)^2 = (x+1)(2x^3 +(3x^2)(x+1)) =

(x + 1)(x^2)(2x+3x + 3) = (x^2)(x+1)(5x+3)

x(x+1)(5x^2+3)