√48 - 2√3 + √20 Can anybody help me work this surd out?

2009-02-08 4:55 am
Can anyone help me work this out
√48 - 2√3 + √20??
Please show the working out
DESPERATE!

回答 (6)

2009-02-08 5:04 am
✔ 最佳答案
√48 - 2√3 + √20
=√(3*16)-2√3+√(4*5)
=4√3-2√3+2√5
=2√3+2√5 answer
2009-02-08 1:04 pm
√48 - 2√3 + √20
= 4√3 - 2√3 + 2√5
= 2√3 + 2√5

Pretend like a square root phrase (i.e. √3) is a variable, and any coefficient can be combined through adding or subtracting only if the variable is the same. Thus, you must reduce √48 to some form of √3 to combine. After that, there is no way to reduce the problem more. If, however, the equation was + √21 (instead of 20), you could convert that to √7√3 (multiplied), then condense:

= 2√3 + √7√3
= (2 + √7)√3
2009-02-08 1:01 pm
First we note the prime factorizations of the values under the roots:

48 = 2 * 2 * 2 * 2 * 3 so √48 = 4√3
20 = 2 * 2 * 5 so √20 = 2√5

Now your expression simplifies to

2√3 + 2√5
2009-02-08 3:14 pm
√48 - 2√3 + √20
= √(4^2 * 3) - 2√3 + √(2^2 * 5)
= 4√3 - 2√3 + 2√5
= 2√3 + 2√5
= 2(√3 + √5)
2009-02-08 1:06 pm
Factoring, we have:
√48|2
24|2
12|2
06|2
03|3
1

√48 = √3 * √2^4 = 2² * √3 = 4√3

√20|2
10|2
05|5
1
√20 = √2² * √5 = 2√5

4√3 - 2√3 + 2√5 = 2√3 + 2√5
2009-02-08 1:05 pm
Answer: (2√3) + (2√5)

Work:
48 breaks up into 4 and 12, 20 breaks up into 4 and 5

√4*√12 -2√3+√4*√5

12 breaks up into 3 and 4

=2√4*√3-2√3+2*√5
=4√3-2√3+2√5
=(2√3)+(2√5)


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