I65
1) x^2+2x+1-y^2=?
2)a^2-2ab+b^2-9x^2=?
3) x^2-a^2-2ab-b^2=?
Factorisation_FROM2 x+y...
2009-02-07 8:17 am
回答 (2)
2009-02-07 9:55 am
✔ 最佳答案
Q1)x^2 + 2x + 1 - y^2
= ( x+1 )^2 - y^2
= [ (x+1)-y ] [ (x+1)+y ]
= ( x+1-y )( x+1+y )
Q2)
a^2 - 2ab + b^2 - 9x^2
= ( a-b )^2 - ( 3x )^2
= [ (a-b)-3x ] [ (a-b)+3x ]
= ( a-b-3x )( a-b+3x )
Q3)
x^2 - a^2 - 2ab - b^2
= x^2 - ( a^2 + 2ab + b^2 )
= x^2 - ( a+b )^2
= [ x-(a+b) ] [ x+(a+b) ]
= ( x-a-b )( x+a+b )
2009-02-07 8:31 am
Q1)
x^2 + 2x + 1 - y^2
= ( x+1 )^2 - y^2
= [ (x+1)-y ] [ (x+1)+y ]
= ( x+1-y )( x+1+y )
Q2)
a^2 - 2ab + b^2 - 9x^2
= ( a-b )^2 - ( 3x )^2
= [ (a-b)-3x ] [ (a-b)+3x ]
= ( a-b-3x )( a-b+3x )
Q3)
x^2 - a^2 - 2ab - b^2
= x^2 - ( a^2 + 2ab + b^2 )
= x^2 - ( a+b )^2
= [ x-(a+b) ] [ x+(a+b) ]
= ( x-a-b )( x+a+b )
2009-02-07 00:32:36 補充：
Next time... please make sure you have enough points to ask question... OK?
x^2 + 2x + 1 - y^2
= ( x+1 )^2 - y^2
= [ (x+1)-y ] [ (x+1)+y ]
= ( x+1-y )( x+1+y )
Q2)
a^2 - 2ab + b^2 - 9x^2
= ( a-b )^2 - ( 3x )^2
= [ (a-b)-3x ] [ (a-b)+3x ]
= ( a-b-3x )( a-b+3x )
Q3)
x^2 - a^2 - 2ab - b^2
= x^2 - ( a^2 + 2ab + b^2 )
= x^2 - ( a+b )^2
= [ x-(a+b) ] [ x+(a+b) ]
= ( x-a-b )( x+a+b )
2009-02-07 00:32:36 補充：
Next time... please make sure you have enough points to ask question... OK?
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