expand: (2x+3)2 - (x+1)(4x-5)????

2009-02-07 7:43 am
how do you work this out?
expand: (2x+3)2(squared) - (x+1)(4x-5)

can someone plz show step by step?
thank you

回答 (7)

2009-02-07 8:33 am
✔ 最佳答案
(2x+3)^2-(x+1)(4x-5)
=(2x+3)(2x+3)-(4x^2-x-5)
=4x^2+12x+9-4x^2+x+5
=13x+14 answer//
2009-02-07 8:35 am
(2x + 3)^2 - (x + 1)(4x - 5)
= (2x + 3)(2x + 3) - (x*4x + 1*4x - x*5 - 1*5)
= 2x*2x + 3*2x + 2x*3 + 3*3 - (4x^2 + 4x - 5x - 5)
= 4x^2 + 6x + 6x + 9 - 4x^2 + x + 5
= 4x^2 - 4x^2 + 12x + x + 9 + 5
= 13x + 14
2009-02-07 8:03 am
well..the formula for:
(x + y)^2
=x^2 + 2xy + y^2
ok..so it goes like this..
(2x + 3)^2 - (x + 1) (4x - 5)
= 4x^2 + 12x + 9 - [4x^2 - 5x + 4x - 5]
= 4x^2 + 12x + 9 - 4x^2 + x + 5
= 13x + 14

hope it helps! :0) all the best! =D
2009-02-07 7:50 am
(2x+3)^2 - (x+1)(4x-5)

=(4x^2+12x+9)-(4x^2-5x+4x-5)

=(4x^2+12x+9)-(4x^2-x-5)

=4x^2+12x+9-4x^2+x+5

=13x+14
2016-10-16 12:53 pm
(2x+a million)/5-(3x+2)/7=-a million 7x5[(2x+a million)/5-(3x+2)/7=-a million] multiply the full equation via 7 and 5 so there heavily isn't anymore fraction 7(2x+a million) -5(3x+2) = (-a million)(7)(5) 14x+7-15x-10=-35 -x=-32 x=32
2009-02-07 8:12 am
(2x+3)2(squared) - (x+1)(4x-5)
= (4x+6)^2 - 4x^2-4x-5
= 16x^2+36-4x^2-4x-5
= 12x^2-4x+31
2009-02-07 7:56 am
(2x+3)2 squared - (x+1) (4x-5)
1. 2 squared is 4 so 4(2x+3)= 8x+12
2. (x+1) (4x-5) use FOIL= 4x squared - 5x then 4x-5
3. combine like terms
(8x+12) - (4x squared - 5x + 4x-5)=
4. final answer= 4x squared + 7x +7


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