第七條
http://i364.photobucket.com/albums/oo87/davis1991411/phy2-1.jpg
phy_ce
2009-02-04 8:02 am
回答 (1)
2009-02-04 8:38 am
✔ 最佳答案
The answer is B.
(K.E. at A) + (DP.E. bet'n A and B) = (Workdone to overcome friction) + (K.E. at B)
(1/2)mvA2 + mgh = fs + (1/2)mvB2
(1/2)(1500)(0.5)2 + (1500)(10)(50-40) = (400)(200) + (1/2)(1500)vB2
187.5 + 150000 = 80000 + 750vB2
750vB2 = 70187.5
Speed of the cart at B, vB = 9.67 m s-1
=
收錄日期: 2021-04-29 18:15:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090204000051KK00006