F.1 Math !!! 急!!即日

1. He should sell the television set for
=$(2700+300)×(1+20%)
=$(3000×120%)
=$(3000×1.2)
=$3600
∴He should sell the television set for $3600.
2a. Let $x be the cost.
(x-7760)/x=3%
x-7760=0.03x
x-0.03x-7760=0
x-0.03x=7760
0.97x=7760
x=7760÷0.97
x=8000
∴The cost is $8000.
The loss per cent
=(8000-7440)/8000
=560÷8000
=7%
∴The loss per cent is 7%.
2b. The selling price
=$8000×(1+10%)
=$(8000×110%)
=$(8000×1.1)
=$8800
∴The selling price is $8800.

1. Cost of television set = $2700 + $300 = $3000
Selling price = $3000*(1+20%) = $3000*1.2 = $3600

2. Cost of machine = $7760 / (1-3% ) = $7760 / 0.97 = $8000
a. loss percentage = $(8000-7440) / $8000 * 100%
= $560 / $8000 * 100% = 7%
b. selling price = $8000*(1+10%) = $8000*1.1=$8800

1 Mike sells his television set at $2700, he will lose $300
=> The cost of TV is 2700+300=3000
To make a profit of 20%
The price should be
3000(1+20%)=3600
2
Let the cost is x
(7760-x)/x=-3%
0.97x=7760
x=8000
if the machine is sold at 7440
(7440-8000)/8000
=-0.07
loss per cent is 7%
(b)
the sellig price
=8000(1+10%)
=8800