中二數學的問題!!!~有10點!!吾該~

Q1)
x( x - 2) + 1 = ( x - 1)2次
x2次 - 2x + 1 = ( x-1)2次
answer: C

Q2)
我覺得問題有少少錯。 如果問題係:
Which of the following is/are identities?
I. (1 + a )2次 = 1 + 2a + a2次
II. p2次 + q2次 = ( p + q )2次
III. -3x + 12 = 3( x - 4)
answer: A) I only

Q3)
(x - 2)(x - 1) - x(x - 1) = Px + Q
x^2 - 3x + 2 - x^2 + x = Px + Q
-2x + 2 = Px + Q
By equating the coefficients:
P = -2
Q = 2

Q4)
4x^2 + 11x - 3 = ( Ax - 1)( x + B)
4x^2 + 11x - 3 = Ax^2 + ABx - x - B
4x^2 + 11x - 3 = Ax^2 + (AB-1)x - B
By equating the coefficients:
A = 4
B = 3

Q5)
( -5y - 8)( -5y - 8).
= ( -5y-8 )^2
= 25y^ + 2(-5y)(-8) + 64
= 25y^ + 80y + 64

Q6)
(p + q^3)(q^3 - p)
= (q^3 + p)(q^3 - p)
= (q^3)^2 - p^2
= q^6 - p^2

Q7)
( 3x + 1)^2 - ( 4x - 3)^2 = Ax^2 + Bx - 8
9x^2 + 6x + 1 - ( 16^2 - 24x + 9 ) = Ax^2 + Bx - 8
-7x^2 + 30x - 8 = Ax^2 + Bx - 8
-7x^2 + 30x = Ax^2 + Bx
By equating the coefficients:
A = -7
B = 30

Q8)
( x - A)^2 + 1 = x^2 + Bx + C
x^2 - 2xA + A^2 + 1 = x^2 + Bx + C
x^2 - 2xA + ( A^2 + 1 ) = x^2 + Bx + C
By equating the coefficients:
B = -2A
C = A^2 +1

Q9)
( x + y )^2 = 64
x^2 + 2xy + y^2 = 64..........(1)
( x - y )^2 = 4
x^2 - 2xy + y^2 = 4.............(2)
eq(1) - eq(2):
4xy = 60
xy = 15

1.A
2.B
3.?
Sorry, no time to do the others