✔ 最佳答案
1.
The O atom can form 2 hydrogen bonds because it has 2 lone pairs of electrons.
Each H atom can form 1 hydrogen bond, and the 2 H atoms can form 2 hydrogen bonds.
Since 1 hydrogen bond links two molecules together, thus the average maximum number of hydrogen bonds is 2 (= (2 + 2)/2).
2.
The N atom can form 1 hydrogen bond because it has 1 lone pair of electrons.
Each H atom can form 1 hydrogen bond, and the 3 H atoms can form 3 hydrogen bonds.
Mole ratio N : H = 1 : 3, and thus the H atoms are in excess to form hydrogen bonds. Averagely, only 1 H atom in each NH3 molecule can form hydrogen bond.
Since 1 hydrogen bond links two molecules together, thus the average maximum number of hydrogen bonds is 1 (= (1 + 1)/2).
3.
The F atom can form 3 hydrogen bonds because it has 3 lone pairs of electrons.
The H atom can form 1 hydrogen bond .
Mole ratio H : F = 1 : 1, and the lone pairs on F atoms are in excess to form hydrogen bonds. Averagely, the F atom only form 1 hydrogen bond.
Since 1 hydrogen bond links two molecules together, thus the average maximum number of hydrogen bonds is 1 (= (1 + 1)/2).
4.
Pure CHCl3 (A) cannot form hydrogen bonds, because the negative charges on the Cl atoms are NOT sufficent enough to form hydrogen bonds.
Pure CH3CHO (B) cannot form hydrogen bonds, becasue the positive charges on the H atoms are NOT sufficient enough to form hydrogen bonds.
The mixture of CHCl3 (A) and CH3CHO (B) can form hydrogen bonds. To form hydrogen bond, the H atom in A is positively charged enough and the O atom in B is negatively charged enough.
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