how do you solve 6q(square)-18q=0 with zero factor property?
回答 (5)
2009-02-02 8:33 am
✔ 最佳答案
6q^2-18q=02q(3q-9)=0
2q=0 3q-9=0
q=0 3q=9
q=3 answer {0,3}
參考: @(^_^)@
2009-02-02 4:30 pm
6q² - 18q = 0
6q² = 18q
6q²/6q = 18q/6q
q = 3
Answer: q = 3
Proof:
6(3)² = 18(3)
6(9) = 54
54 = 54
6q² = 18q
6q²/6q = 18q/6q
q = 3
Answer: q = 3
Proof:
6(3)² = 18(3)
6(9) = 54
54 = 54
2009-02-02 7:28 pm
6q^2 - 18q = 0
6(q^2 - 3q) = 0
q^2 - 3q = 0
q(q - 3) = 0
q = 0
q - 3 = 0
q = 3
â´ q = 0 , 3
6(q^2 - 3q) = 0
q^2 - 3q = 0
q(q - 3) = 0
q = 0
q - 3 = 0
q = 3
â´ q = 0 , 3
2009-02-02 4:21 pm
what is zero factor? anyway,
6q(square)-18q=0 since q is a factor in both terms, q=0 or :
6q²=18q
q²=3q
q=3
6q(square)-18q=0 since q is a factor in both terms, q=0 or :
6q²=18q
q²=3q
q=3
2009-02-02 4:21 pm
6q^2 - 18q = 0
2q^2 - 3q = 0 -- Dividing by 3, to simplify it a bit.
q(2q - 3) = 0 -- Factorising.
Therefore q = 0, or q = 3/2.
2q^2 - 3q = 0 -- Dividing by 3, to simplify it a bit.
q(2q - 3) = 0 -- Factorising.
Therefore q = 0, or q = 3/2.
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