Need help solving a square root problem?
回答 (7)
2009-01-31 10:58 am
✔ 最佳答案
√x - 9 = 7√x = 7+9 (moving 9 to another side, sign changes from - to +)
√x = 16
(√x)^2 = 16^2 (squaring both sides)
x = 256.( when u square √x, u get x)
2009-01-31 6:56 pm
âx - 9 = 7
âx = 16
x = 256
Assuming it is just âx and not â(x-9)
âx = 16
x = 256
Assuming it is just âx and not â(x-9)
2009-01-31 10:48 pm
âx - 9 = 7
âx = 7 + 9
x = 16^2
x = 256
âx = 7 + 9
x = 16^2
x = 256
2009-01-31 7:04 pm
the ans is simple just remember the simple BODMAS.
âx=7+9
=16
therefore, x=16's square i.e.16*16
therefore, x=256.
Thanks & Regards.
âx=7+9
=16
therefore, x=16's square i.e.16*16
therefore, x=256.
Thanks & Regards.
2009-01-31 7:01 pm
âx-9=7
you next move 9 on te oder side of = and get
âx=7+9
add
âx=16
then you calculate how much is 16 ^2
and you get
x=256
you next move 9 on te oder side of = and get
âx=7+9
add
âx=16
then you calculate how much is 16 ^2
and you get
x=256
參考: if you had âx=4, you would do: 4^2=>x=16
if you had âx=10 you would do 10^2=>x=100
and, if you had âx=5, you would had 5^2=>x=25
Hope it helps.. ;)
2009-01-31 6:59 pm
Is it the square root of (x-9) or the square root of x, then -9?
If it's the latter, SqR X=7+9 > X=(7+9) Squared.
I think you remember now.
If it's the latter, SqR X=7+9 > X=(7+9) Squared.
I think you remember now.
2009-01-31 6:57 pm
âx = 7+9 = 16
x = 16^2 = 256
x = 16^2 = 256
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