F(x) = x log(3x + 4)
find dy/dx
maths derivative4
2009-01-28 9:48 am
回答 (2)
2009-01-29 6:20 am
✔ 最佳答案
y=F(x)= x log(3x+4)
= x ln(3x+4) / ln 10
dy/dx
= (1 / ln 10) * ( ln(3x+4)*1 + x * 1 / (3X+4) *3 )
= (1 / ln 10) * ( ln(3x+4) + 3x / (3X+4) )
參考: Myself
2009-01-28 10:28 am
if y=xln(3x+4)
dy/dx
=d/dx[xln(3x+4)]
=ln(3x+4)+3x/(3x+4)
dy/dx
=d/dx[xln(3x+4)]
=ln(3x+4)+3x/(3x+4)
收錄日期: 2021-04-26 13:04:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090128000051KK00138