5 over (x^2) + 1 over (x^2 +x) Anyone! please help!?

If it were 5 over 8 + 1 over 12 you wouldn't hesitate: Multiply the denominators to find a common denom., convert the given fractions to equivilent fractions with the common denom. and add. Do the same thing: Multiply denominators: (x^2) x (x^2 + x) = x^4 + x^3
5 over x^2 = 5x^2 + 5x over x^4 + x^3
1 over x^2 + x = x^2 over x^4 + x^3
Add the numerators: 5x^2 + 5x + x^2 yields 6x^2 +5x over x^4 + x^3
Now, can't you get rid of one "x"? I think the answer is 6x +5 over x^3 + x^2

5/(x^2+1)/(x^2+x)

= 5/(x^2+1)(x^2+x)

5/x^2 + 1/(x^2 + x)
= 5/x^2 + 1/x(x + 1)
= 5(x + 1)/x^2(x + 1) + 1(x)/x^2(x + 1)
= (5x + 5)/x^2(x + 1) + x/x^2(x + 1)
= (5x + 5 + x)/x^2(x + 1)
= (6x + 5)/x^2(x + 1)

(5(x+1)+x)/x^2(x+1)
=(6x+5)/x^2(x+1)