equation~~plz help

The reaction is stepwise. When dilute hydrochloric acid is added dropwise until excess, a white precipitate of zinc hydroxide is firstly formed and then dissolved in excess hydrochloric acid.

Equation for the formation of the white precipitate of zinc hydroxide:
K2Zn(OH)4(aq) + 2HCl(aq) → 2KCl(aq) + Zn(OH)2(s) + 2H2O(l)
or: Zn(OH)42-(aq) + 2H+(aq) → Zn(OH)2(s) + 2H2O(l)

Equation for the redissolving of the white precipitate of zinc hydroxide:
Zn(OH)2(s) + 2HCl(aq) → ZnCl2(aq) + 2H2O(l)
or: Zn(OH)2(s) + 2H+(aq) → Zn2+(aq) + 2H2O(l)



The overall equation of the reaction is:
K2Zn(OH)4(aq) + 4HCl(aq) → 2KCl(aq) + ZnCl2(aq) + 4H2O(l)
or: Zn(OH)42-(aq) + 4H+(aq) → Zn2+(aq) + 4H2O(aq)
=