Math factorisation ?

2009-01-24 1:27 pm
Now, I'm usually really good at factorisation, but this question completely threw me off..

Factorise 3m² + 4m

Now I'm used to questions like x² - 3x - 4 in which case the answer would be (x - 4) (x + 1). The question above I have been given is really fustrating for me because I don't know where to start really.

I think I would start with something like (3m.....) (m......) but I'm not sure where I would go from there. Any guidance would be geat

回答 (8)

2009-01-24 2:06 pm
✔ 最佳答案
well, all you need is to use simple thinking.. do not hurt your brain and think of all the complicated stuff =) that will only cause confusion

anyway... see what's common in both of them...that will be m..so::


3m² + 4m
= m( 3m + 4)

hope that helped =)
2009-01-24 4:36 pm
3m^2 + 4m
= m(3m + 4)
2009-01-24 1:39 pm
3m^2+4m
=m(3m+4) answer//

GCF: is m
2009-01-24 1:39 pm
Factoring only means to write as a product in an interesting way... for example

3m² + 4m = m(3m+4)

But

3m² + 4m = 1(3m² + 4m) wouldn't be considered factoring, since 1 is a unit . Similarly 3(m² + 4/3m) wouldn't be factoring over the polynomials since 3 is a unit (it has a reciprocal). Also 3m² + 4m = 3/m(m^3+4/3 m^2) wouldn't be considered factoring over the polynomials since 3/m isn't a polynomial.

Think "express as an interesting product, but not too interesting" when someone says to factor something.
2009-01-24 1:38 pm
both 4m and 3m^2 have m in common,so you can factorise m.
so 3m^2+4m=m(3m+4)
2009-01-24 1:36 pm
3(m+(2/3))^2-(4/3)

completing the square method.
2009-01-24 1:34 pm
You can at best take 'm' common and write as 3m² + 4m =m(3m + 4)
When you think about usual methods and not the question in hand, the result is usually confusion
2009-01-24 1:32 pm
3m² + 4m = m(3m + 4)


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