solve for the value of x?
回答 (4)
2009-01-21 1:22 pm
✔ 最佳答案
x^2 + 12x = -32x^2 + 12x + 32 = 0
(x + 4)(x + 8) = 0
x = -4 or x = -8
2009-01-21 11:14 pm
x^2 + 12x = -32
x^2 + 12x + 32 = 0
x^2 + 8x + 4x + 32 = 0
(x^2 + 8x) + (4x + 32) = 0
x(x + 8) + 4(x + 8) = 0
(x + 8)(x + 4) = 0
x + 8 = 0
x = -8
x + 4 = 0
x = -4
â´ x = -8 , -4
x^2 + 12x + 32 = 0
x^2 + 8x + 4x + 32 = 0
(x^2 + 8x) + (4x + 32) = 0
x(x + 8) + 4(x + 8) = 0
(x + 8)(x + 4) = 0
x + 8 = 0
x = -8
x + 4 = 0
x = -4
â´ x = -8 , -4
2009-01-21 8:34 pm
x=-6+-(36-32)^1/2=-8&-4
2009-01-21 8:29 pm
x^2 +12x + 32=0
(x + 4)(x + 8)=0
x = -4 or -8
(x + 4)(x + 8)=0
x = -4 or -8
收錄日期: 2021-05-01 11:53:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090121042322AAkCNSD