a) four aces
b) three aces and two jacks
c) three aces and a pair
更新1:
why multiplying 10?
Card games
2009-01-22 6:05 am
draw five cards from a standard deck and get
a) four aces
b) three aces and two jacks
c) three aces and a pair
a) four aces
b) three aces and two jacks
c) three aces and a pair
回答 (2)
2009-01-22 6:52 am
✔ 最佳答案
Say the probability for incedent E to occur as P(E).P(4 Aces)=4/52*3/51*2/50*1/49*5=1/54145=0.001847%(4 sig. fig.)
P(3 Aces + 2 Jacks)=4/52*3/51*2/50*4/49*3/48*10=1/108290=0.0009234%(4 sig. fig.)
P(3 Aces + Pair)=4/52*3/51*2/50*48/49*3/48*10=6/54145=0.01108%(4 sig. fig.)
2009-01-23 2:41 am
why multiplying 10?
Think about when two jacks and three aces are filled into 5 boxes, how many arrangements can there be.
J J A A A
J A J A A
J A A J A
J A A A J
A J J A A
A J A J A
A J A A J
A A J J A
A A J A J
A A A J J
or by binomial distribution,
5C2 = 10
Think about when two jacks and three aces are filled into 5 boxes, how many arrangements can there be.
J J A A A
J A J A A
J A A J A
J A A A J
A J J A A
A J A J A
A J A A J
A A J J A
A A J A J
A A A J J
or by binomial distribution,
5C2 = 10
收錄日期: 2021-04-24 00:16:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090121000051KK01785