Braille system

2009-01-22 12:54 am
Each Braille character or cell is made up of six dot positions, arranged in a rectangle containing two columns of three dots each. A dot may be raised at any of the six positions to form sixty-four (26) permutations, including the arrangement in which no dots are raised

2^6 = 64 different symblos??

a) How many symbols have exactly three raised dots?
b) How many symbols have an even number of raised dots?
更新1:

but then how can I know how many symbols have exactly three raised dots and an even number of raised dots?

回答 (1)

2009-01-22 3:20 am
✔ 最佳答案
We can solve this question by consider its simplified form.

Consider the form with 1 dot position.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 1
Total number of possible symbols = 1+1 = 2

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Consider the form with 2 dot positions.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 2
Number of symbols have 2 raised dots = 1
Total number of possible symbols = 1+2+1 = 4 = 2^2

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Consider the form with 3 dot positions.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 3
Number of symbols have 2 raised dots = 3
Number of symbols have 3 raised dots = 1
Total number of possible symbols = 1+3+3+1 = 8 = 2^3

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Notice that the pattern of "Pascal's Triangle" is seen.
***************

Consider the form with 4 dot positions.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 4
Number of symbols have 2 raised dots = 6
Number of symbols have 3 raised dots = 4
Number of symbols have 4 raised dots = 1
Total number of possible symbols = 2^4 = 16

***************

Consider the form with 5 dot positions.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 5
Number of symbols have 2 raised dots = 10
Number of symbols have 3 raised dots = 10
Number of symbols have 4 raised dots = 5
Number of symbols have 5 raised dots = 1
Total number of possible symbols = 2^5 = 32

2009-01-21 19:21:33 補充:
Now, consider the form with 6 dot positions, the true form of Braille system.

Number of symbols have 0 raised dots = 1
Number of symbols have 1 raised dots = 6
Number of symbols have 2 raised dots = 15
Number of symbols have 3 raised dots = 20

2009-01-21 19:21:43 補充:
Number of symbols have 4 raised dots = 15
Number of symbols have 5 raised dots = 6
Number of symbols have 6 raised dots = 1
Total number of possible symbols = 2^6 = 64

2009-01-21 19:21:51 補充:
a) The numbers of symbols have 3 raised dots = 20

b) The numbers of symbols have an even number of raised dots = 15+15+1 = 31 (If 0 is excluded) or 1+15+15+1 = 32 (If 0 is included)
參考: Self-Evaluation


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