✔ 最佳答案
S1 = 3 + 5 + 7 + ......... + 2005 + 2007 是等差級數的和
T(1) = a = 3
T(n) = l = 2007
d = 2
T(n) = a + (n - 1)d
2007 = 3 + (n - 1)(2)
n = 1003
S1
= n(a + l)/2
= 1003(3 + 2007)/2
= 1008015
S2 = 4 + 6 + 8 + ......... + 2004 + 2006 是等差級數的和
T(1) = a = 4
T(n) = l = 2006
d = 2
T(n) = a + (n - 1)d
2006 = 4 + (n - 1)(2)
n = 1002
S2
= n(a + l)/2
= 1002(4 + 2006)/2
= 1007010
3 - 4 + 5 - 6 +......+ 2003 - 2004 + 2005 - 2006 + 2007
= (3 + 5 + 7 + ..... + 2007) - (4 + 6 + 8 + ...... + 2006)
= S1 - S2
= 1008015 - 1007010
= 1005
=