How do you prove 10^0 = 1?
回答 (7)
2009-01-18 2:03 pm
✔ 最佳答案
We know that ---x^a / x^a = 1
But from the law of indices we get --
=> x^(a-a) = 1
=> x^0 = 1
where x is any non-zero number. Now if we put x = 10 we get :-
=> 10^0 = 1 .................... Proved
Dr P.K.Tandon
........................................................
2009-01-18 9:41 am
2009-01-18 9:53 am
(10^2)/(10^2)
= 10^(2 - 2) (= 100/100)
= 10^0 (= 1)
= 1
= 10^(2 - 2) (= 100/100)
= 10^0 (= 1)
= 1
2009-01-18 9:50 am
10^(a-b)=10^a/10^b is true so if a=b 10^a/10^a=1
with numbers as an example
10^0=10^(3-3)=10^3/10^3 ------> the right side is 1
with numbers as an example
10^0=10^(3-3)=10^3/10^3 ------> the right side is 1
2009-01-18 9:47 am
By laws of indices anything(except for 0) to the power of 0 is equal to1
Thus 10^0=1
Thus 10^0=1
2009-01-18 9:45 am
use logarithms
log 10^0 = log 1
0log10 = log 1
0*1 =0
0 = 0
log 10^0 = log 1
0log10 = log 1
0*1 =0
0 = 0
2009-01-18 9:44 am
ok i will show you how to prove anything to the power of 0=1
1^1=1
1^1 divided by 1^1 = 1^(1-1) but 1 divided by 1 = 1
therefore 1^(1-1)= 1^0=1
therefore anything to the power of 0=1
1^1=1
1^1 divided by 1^1 = 1^(1-1) but 1 divided by 1 = 1
therefore 1^(1-1)= 1^0=1
therefore anything to the power of 0=1
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