Maths!!! (送分)

The height of Carol is 156.0 cm( correct to nearest 0.2 cm). Find the
maximum absolute error, upper limit and lower limit of the height of
Carol.

請不要誤會，以為 0.2 cm 就係 Maximum absolute error!

你回答呢條問題就知點解。

On the following number line, if all numbers are corrected to the nearest 0.2, what is the next one?


---------------l---------------l---------------l---------->
155.8 156.0 ?

The answer is 156.2, because every number is corrected to tne nearest 0.2.

From the mathematics textbooks,

The formular for Maximum absolute error is

0.5 x difference between the finest marking on the mearsuring tool. (你地應該知道架!)

Therefore, in the above case,
the maximum absolute error is 0.5 x 0.2 = 0.1.

Using the above explaination,
Back to your case:

Maximum absolute error
= 0.5 x 0.2 cm
= 0.1 cm


The upper limit of her height
= (156 + 0.1) cm
= 156.1 cm


The lower limit of her height
= (156 - 0.1) cm
= 155.9 cm

Maxium absolute error= 0.5*0.2cm
= 0.1cm

Upper limit= 156cm+0.1cm
= 156.1cm

Lower limit= 156cm-0.1cm
= 155.9cm

The height of Carol is 156.0 cm( correct to nearest 0.2 cm). Find the
maximum absolute error, upper limit and lower limit of the height of
Carol.



maximum absolute error=0.2 cm

Upper limit=x+maximum absolute error
=156.0cm+0.2cm
=156.2cm
Lower limit=x-maximum absolute error
=156.0cm-0.2cm
=155.8cm

maximum absolute error=0.2 cm

Upper limit=x+maximum absolute error
=156.0cm+0.2cm
=156.2cm
Lower limit=x-maximum absolute error
=156.0cm-0.2cm
=155.8cm

The height of Carol is 156.0 cm( correct to nearest 0.2 cm). Find the
maximum absolute error, upper limit and lower limit of the height of
Carol.


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The height of Carol is 156.0 cm( correct to nearest 0.2 cm). Find the
maximum absolute error, upper limit and lower limit of the height of
Carol.