Can anyone tell me the LCM?
回答 (5)
2009-01-15 6:45 am
✔ 最佳答案
v^3 + 8v^2 + 16v=v(v^2+8v+16)
=v(v+4)(v+4) <-----LCM
and
v^2-8v
=v(v-8) <----LCM
2009-01-15 3:04 pm
v^3 + 8v^2 + 16v = v(v + 4)^2
v^2 - 8v = v(v - 8)
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The LCM of v^3 + 8v^2 + 16v and v^2 - 8v is:
v(v + 4)^2(v - 8)
= v(v + 4)(v + 4)(v - 8)
= v(v^2 + 8v + 16)(v - 8)
= v(v^3 + 8v^2 + 16v - 8v^2 - 64v - 128)
= v(v^3 - 56v - 128)
= v^4 - 56v^2 - 128v
v^2 - 8v = v(v - 8)
-------------------------------------------
The LCM of v^3 + 8v^2 + 16v and v^2 - 8v is:
v(v + 4)^2(v - 8)
= v(v + 4)(v + 4)(v - 8)
= v(v^2 + 8v + 16)(v - 8)
= v(v^3 + 8v^2 + 16v - 8v^2 - 64v - 128)
= v(v^3 - 56v - 128)
= v^4 - 56v^2 - 128v
2009-01-15 2:42 pm
lcm -leats common denomiator would be just v
2009-01-15 2:40 pm
factor v^3 + 8v^2 + 16v
v(v^2+8v+16)
v(v+4)(v+4)
factor
v^2 - 8v
v(v-8)
v is the only common factor
v(v+4)(v+4)(v-8)
v(v^2+8v+16)
v(v+4)(v+4)
factor
v^2 - 8v
v(v-8)
v is the only common factor
v(v+4)(v+4)(v-8)
2009-01-15 2:39 pm
LCM would be v*(v-8)*(v+4)^2
收錄日期: 2021-05-01 11:53:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090114223437AASLeQM