1. x + 6x + 8 = 0
2. 6x2 – 20x + 16 = 0
3. 6x + 5x = 6
送分題,一元二次方程
2009-01-14 7:59 pm
回答 (3)
2009-01-14 8:04 pm
✔ 最佳答案
1/. x + 6x + 8 = 0(x+2)(x+4) = 0
X=-2 or -4
2/. 6x2 – 20x + 16 = 0
(3x-4)(2x-4) = 0
X=4/3 or 2
3/. 6x + 5x = 6
11x = 6
X=6/11
2009-01-14 9:19 pm
1.x² + 6x + 8 = 0
(x+2)(x+4)=0
x= -2 or x= -4
2. 6x^2 – 20x + 16 = 0
(x-2)(4x-3)=0
x= 2 or x=4/3
3. 6x+5x=6
11x=6
x=6/11
i hope i can help you la^^
(x+2)(x+4)=0
x= -2 or x= -4
2. 6x^2 – 20x + 16 = 0
(x-2)(4x-3)=0
x= 2 or x=4/3
3. 6x+5x=6
11x=6
x=6/11
i hope i can help you la^^
2009-01-14 8:10 pm
1. x² + 6x + 8 = 0
(x + 4)(x + 2) = 0
x1 = -4 x2 = -2
2. 6x²– 20x + 16 = 0
3x² - 10x + 8 = 0
(3x - 4)(x - 2) = 0
x1 = 4/3 x2 = 2
3. 6x + 5x = 6
11x = 6
x = 6/11
(x + 4)(x + 2) = 0
x1 = -4 x2 = -2
2. 6x²– 20x + 16 = 0
3x² - 10x + 8 = 0
(3x - 4)(x - 2) = 0
x1 = 4/3 x2 = 2
3. 6x + 5x = 6
11x = 6
x = 6/11
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