How do you factorize 4y²-9?
回答 (8)
2009-01-13 4:57 pm
✔ 最佳答案
4y^2-9=(2y+3)(2y-3) answer
2009-01-14 1:07 am
( 2y - 3 ) ( 2y + 3 )
2009-01-14 1:01 am
a^2 - b^2 = (a + b)(a - b)
4y^2 - 9
= (2y)^2 - 3^2
= (2y + 3)(2y - 3)
4y^2 - 9
= (2y)^2 - 3^2
= (2y + 3)(2y - 3)
2009-01-14 12:58 am
(2y+3)(2y-3)
2009-01-14 12:55 am
This is a difference of squares.
It will factor into (2y+3)(2y-3).
http://regentsprep.org/Regents/math/factor/Lfactps.htm
It will factor into (2y+3)(2y-3).
http://regentsprep.org/Regents/math/factor/Lfactps.htm
2009-01-14 12:54 am
Factor a^2-b^2.
2009-01-14 12:54 am
4y²-9 = (2y-3) (2y+3)
2009-01-14 12:55 am
it can b riten in to ((2y)^2-3^2)
u can also rit it as (2y-3)(2y+3)
u can also rit it as (2y-3)(2y+3)
收錄日期: 2021-05-01 11:51:16
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