(3/z)=(5/y)+(2/x) solve for x?

3/z=5/y+2/x
3/z-5/y=2/x
(3y-5z)/yz=2/x
yz/(3y-5z)=x/2
x=2yz/(3y-5z)
The value of x depends on the variables y and z.

3/z = 5/y + 2/x
2/x = 3/z - 5/y
x = 2/(3/z - 5/y)
x = 2/(3y/yz - 5z/yz)
x = 2/[(3y - 5z)/yz]
x = 2[yz/(3y - 5z)]
x = 2yz/(3y - 5z)

3/z = 5/y + 2/x subtract 5/y from both sides
3/z-5/y=2/x multiply both sides by x
x(3/z-5/y)=2 divide both sides by (3z-5/y)
x=2/(3z-5/y)

3/z - 5/y = 2/x
(3y-5z)/zy = 2/x
x = 2zy/(3y-5z)