v=(2+x)/(3-x) Find x. Any help would be great?

V=(2+x)
...----------
......3-x

V(3-x)=2+x we cross mulitiply
3V-Vx=2+x
3V-2=x+Vx
3V-2=x(1+V)
x=3V-2/1+V answer

v = (2 + x)/(3 - x)
3v - vx = 2 + x
vx + x = 3v - 2
x(v + 1) = 3v - 2
x = (3v - 2)/(v + 1)

Answer: x = (3v - 2)/(v + 1)

v = (2 + x)/(3 - x)
v(3 - x) = 2 + x
3v - vx = 2 + x
x + vx = 3v - 2
x(1 + v) = 3v - 2
x = (3v - 2)/(v + 1)

v (3 - x) = 2 + x
3v - v x = 2 + x
3v - 2 = (1 + v) x
x = (3v - 2) / (1 + v)

V=(2+X)/3-X then you cross muitply
V(3-X)=2+X
3V-VX=2+X
-VX-X=2-3V
X(-V-1)=2-3V
X(-V-1)/(-V-1)=(2-3V)/(-V-1)
X=(2-3V)/-V-1

x=1/2, v=1

The work of the previous person is correct except for the answer:

v=(2+x)/(3-x)
(3-x)v = 2+x
3v-vx-x = 2
3v-x(v+1) = 2
3v-2 = x(v+1)
x = (3v-2) / (V+1)

what do you mean by this V is this just a constant?
v=(2+x)/(3-x)
(3-x)v = 2+x
3v-vx-x = 2
3v-x(v+1) = 2
3v-2 = x(v+1)
x = 3v-2/v+1