one problem addition/subtraction fraction in algebra 1 hel needed!?

x/(2x - 1) + (x - 1)/(2x + 1) - 2x/(4x^2 - 1)
= x(2x + 1)/(2x + 1)(2x - 1) + (x - 1)(2x - 1)/(2x + 1)(2x - 1) - 2x/(2x + 1)(2x - 1)
= (2x^2 + x)/(2x + 1)(2x - 1) + (2x^2 - 2x - x + 1)/(2x + 1)(2x - 1) - 2x/(2x + 1)(2x - 1)
= (2x^2 + x + 2x^2 - 3x + 1 - 2x)/(2x + 1)(2x - 1)
= (2x^2 + 2x^2 + x - 3x - 2x + 1)/(2x + 1)(2x - 1)
= (4x^2 - 4x + 1)/(2x + 1)(2x - 1)
= (4x^2 - 2x - 2x + 1)/(2x + 1)(2x - 1)
= [(4x^2 - 2x) - (2x - 1)]/(2x + 1)(2x - 1)
= [2x(2x - 1) - 1(2x - 1)]/(2x + 1)(2x - 1)
= (2x - 1)(2x - 1)/(2x + 1)(2x - 1)
= (2x - 1)/(2x + 1)

4x+6y=sixteen .................. (a million) 3x-2y= - a million .....................(2) Multiply eqn (2) by 3 and upload equation (a million) 4x + 6y + 9x - 6y = sixteen + (-3) 13x = 13 Divide by 13, we get x = a million Now sub x = a million in equation (a million) we get 4(a million) + 6y = sixteen 6y = 12 Divide by 2 y =2 (answer) Now attempt your self.

Question is incorrect on a number of fronts.
Missing + or - sign before 2x/4x²
Missing brackets around 2x - 1 , 2x + 1 , 4x² - 1 presumably.