更新1:
steps please!
solve for y: xy-3x=30 I so far have xy=33 ?
回答 (8)
2009-01-12 6:23 am
✔ 最佳答案
This isn't very hard actually lets look at the problem:xy-3x=30
well lets divide add 3x to both sides:
we are left with xy=30+3x
now lets divide both sides by x
we are left with y=30+3 because the x's cancel out
so now we are left with y=30+3
so you=33
2009-01-12 6:31 am
xy - 3x = 30
xy = 3x + 30
y = (3x + 30)/x
y = 3x/x + 30/x
y = 3 + 30/x
xy = 3x + 30
y = (3x + 30)/x
y = 3x/x + 30/x
y = 3 + 30/x
2009-01-12 6:07 am
xy-3x=30
x(y-3) = 30
(y-3) = 30/x this is a rectangular Hyperbola
y = 30/x + 3 the hyperbolic has asymptotes x=0 and y= 3
note
(x-a) & (y-b) move{translate} the origin to (a,b)
x(y-3) = 30
(y-3) = 30/x this is a rectangular Hyperbola
y = 30/x + 3 the hyperbolic has asymptotes x=0 and y= 3
note
(x-a) & (y-b) move{translate} the origin to (a,b)
2009-01-12 6:04 am
xy-3x=30 add 3x to both sides
xy = 30+3x then divide both sides by x
y = (30+3x)/x
y = 3(10+x)/x
xy = 30+3x then divide both sides by x
y = (30+3x)/x
y = 3(10+x)/x
2009-01-12 6:02 am
y=(30+3x)/x
2009-01-12 6:02 am
y = (30+3x)/x
2009-01-12 6:01 am
xy - 3x = 30
y -3 = 30/x
y = 30/x -3
y -3 = 30/x
y = 30/x -3
2009-01-12 6:01 am
y=(30+3x)/x
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090111215628AAq4mSg