可唔可以幫手計多項式???

2009-01-11 9:23 pm
化簡:
1.(2a+3b-4)+(5a-b+7)

2.(7c-8d-11)-(-c+8d+2)

3.(2x^2-3x+5)+(x^2-7x-9)

4.(1-c-c^2)+(2c+3c^2)

用展開法展開下列各式:

5.(x+1)(x^2+x+1)

6.(x^2-x+2)(x-1)

7.(x^2-2x+7)(x+3)

8.(x+2)(x^3+x^2-6x)

用長乘法展開下列各式:

9.(x+2)(x^2-2x-1)

10.(x^2+5x+3)(x-2)

11.(x^2-3x+5)(x+8)

12.(x-7)(x^3-x^2-2x)

求下列各題的商式:

13.(2x^2-5x-12) / (x-4)

14.(-x^2-2x+3) / (x-1)

15.(-2x^2-15x-27) / (x+3)

16.(-3x^2+26x-35) / (x-7)

求下列各題的商式及餘式:

17.(x^2+2x+3) / x

18.(-7x^4+9x^2) / (-x)

19.(x^2-4x+5) / (x-1)

20.(2x^2-7x+11) / (x-2)

21.(4k^3-2k^2+5k-12) / (2k^2-k+3)

22.(2y^3-2y^2+1) / (2y^2-1)

挑戰題:

23.(2x^2-3x+1)(2-3x)

回答 (2)

2009-01-26 9:04 pm
✔ 最佳答案
化簡:
1.(2a+3b-4)+(5a-b+7)
=2a+3b-4+5a-b+7
=7a-2b+3
(x+1)(x2+x+1)
=x3+x2+x+x2+x+1
=x3+2x2+2x+1

23.挑戰題:

(2x2-3x+1)(2-3x)
=4x2-6x3-6x+9x2+2-3x
=-6x3+13x2-9x+2

意見補充


圖片參考:http://tw.yimg.com/i/tw/ugc/rte/smiley_27.gif



2009-01-26 13:11:02 補充:
用長乘法展開下列各式:

9.(x+2)(x^2-2x-1)
=x^3-2x^2-x+2x^2-4x-2
=x^3-5x-2


求下列各題的商式:

13.(2x^2-5x-12) / (x-4)

商式:2x+3


求下列各題的商式及餘式:

17.(x^2+2x+3) / x

商式:2x+3
餘式:3

………
2009-01-26 12:56 am
點解你會有咁多題目嫁~??
功課要自己做嫁麻= ="
乜你咁懶嫁= ="

2009-01-25 16:58:44 補充:
多到咁.....
人地都未必咁有心機幫你答喇
叫人點答喎~=3=


收錄日期: 2021-04-13 16:21:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090111000051KK00719

檢視 Wayback Machine 備份