Can you help me solve the following with a step-by-step example?
4^1/3 over 8^1/5
Algebra Two Problem:?
2009-01-11 7:10 am
回答 (5)
2009-01-11 7:15 am
✔ 最佳答案
since 4 = 2² and 8 = 2³,4^(1/3) = 2^(2/3) and 8^(1/5) = 2^(3/5), so we have
2^(2/3) / 2^(3/5) = 2^( 2/3 - 3/5) = 2^(10/15 - 9/15) = 2^(1/15)
2009-01-11 3:16 pm
to hard to explain.
depends on the calculator
depends on the calculator
2009-01-11 5:43 pm
4^(1/3)/8^(1/5)
= (2^2)^(1/3)/(2^3)^(1/5)
= 2^(2 * 1/3)/2^(3 * 1/5)
= 2^(2/3)/2^(3/5)
= 2^(2/3 - 3/5)
= 2^(10/15 - 9/15)
= 2^(1/15)
= (2^2)^(1/3)/(2^3)^(1/5)
= 2^(2 * 1/3)/2^(3 * 1/5)
= 2^(2/3)/2^(3/5)
= 2^(2/3 - 3/5)
= 2^(10/15 - 9/15)
= 2^(1/15)
2009-01-11 4:14 pm
4^(1/3)
--------
8^(1/5)
2^(2/3)
---------
2^(3/5)
2^(10/15)
------------
2^(9/15)
2^(1/15)
--------
8^(1/5)
2^(2/3)
---------
2^(3/5)
2^(10/15)
------------
2^(9/15)
2^(1/15)
2009-01-11 3:21 pm
4^1/3 over 8^1/5
13/4 / 41/8
13/4 * 8/41 / (41/8 *8/41)
13/4 * 8/41 = 104/164
104/164 = 52/82 = 26/41
13/4 / 41/8
13/4 * 8/41 / (41/8 *8/41)
13/4 * 8/41 = 104/164
104/164 = 52/82 = 26/41
收錄日期: 2021-05-01 11:48:32
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