how would i solve 5x + 3y = 145 and x + y = 35?

5x + 3y = 145 Eq. (1)
x + y = 35 Eq. (2)

Eliminate y to solve for x
5x + 3y = 145 Eq. (1)
3x + 3y = 105 Eq. (2) x 3
---------subtract----------------
5x - 3x = 145 - 105
2x = 40
x = 40/2 = 20

Eliminate x to solve for y
5x + 5y = 175 Eq. (2) x 5
5x + 3y = 145 Eq. (1)
-------subtract----------------
5y - 3y = 175 - 145
2y = 30
y = 30/2 = 15

(x, y) = (20, 15)

5x + 3y = 145
- 3x - 3y = - 105----ADD

2x = 40
x = 20

20 + y = 35
y = 15

x = 20 , y = 15

5x + 3y = 145 (solve by using elimination)
x + y = 35

x + y = 35
3(x + y) = 3(35)
3x + 3y = 105

...5x + 3y = 145
‒) 3x + 3y = 105 (subtraction)
-------------------------
2x = 40

2x = 40
x = 40/2
x = 20

x + y = 35
20 + y = 35
y = 35 - 20
y = 15

∴ x = 20 , y = 15

5x+3y=145------(1)
x+y=35-----------(2)

|| +5 +3 ||*|| x ||=|| 145 ||=>
|| +1 +1 ||*|| y ||..|| 35 ..||

|| x ||=(1/2)|| 1 -3 ||*|| 145 ||=>
|| y ||........|| -1 5.||..|| 35 .||

|| x ||=|| 20 ||
|| y ||..||15 ||

Solution is (20,15)

5x + 3y = 145
-3x - 3y = -105 ... multiply second equation by -3 .


2x = 40 , y = 35 - x

x = 20
y = 15

x=35-y=> in the first ec. 5(35-y)+3y=145<=>
175-2y=145=> y=15=>x=20