圖片參考：http://hk.geocities.com/stevieg_1023/0MS.gif
更新1:
thanks
M&S integration problem...
2009-01-08 2:38 am
回答 (2)
2009-01-08 2:58 am
✔ 最佳答案
1. u= x+√(x^2+ a) ,du/dx=[ 1+ x/√(x^2+a)]=[√(x^2+a) + x]/√(x^2+a)]
2. du = u/√(x^2+a) dx => dx/√(x^2+a) = du/u
=>∫ dx/√(x^2+a)
= ∫du/u = ln|u|+c
= ln| x+√(x^2+a) | + c
2009-01-07 19:13:15 補充：
There is a nice hint in your question.
參考: me
2009-01-08 2:48 am
could you please email me the photo for the question?
email: [email protected]
email: [email protected]
收錄日期: 2021-04-22 00:33:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090107000051KK01282