可以幫忙解下列各二次方程嗎???(詳細算式)

2009-01-08 2:16 am
1.(x+3)(2x+1)+3=0

2.(3x+1)(1-2x)+4=0

3.x^2-3x(x-5)=25

4.2y(19-4y)=35

5.15(y^2+1)=34y

6.(x-4)(6x+3)=3(3-2x)

7.5x(x-2)=(x-2)^2

8.3y(y-6)=y^2-36

9.(2x-5)^2=(x-3)(2x-5)

10.(x+1)^2+3(x+1)-4=0

回答 (3)

2009-01-08 2:37 am
✔ 最佳答案
1.(x+3)(2x+1)+3=0
2x^2+X+6X+3+3=0
2x^2+7x+6=0
x=-1.5 or -2

2.(3x+1)(1-2x)+4=0
3x-6x^2+1-2x+4=0
-6x^2+x+5=0
x= 1 or -5/6


3.x^2-3x(x-5)=25
x^2-3x^2+15x-25=0
-2x^2+15x-25=0
x= 2.5 or 5


4.2y(19-4y)=35
38y-8y^2-35=0
y= 1.25 or 3.5


5.15(y^2+1)=34y
15y^2+15-34y=0
y= 1 or 1+2/3

6.(x-4)(6x+3)=3(3-2x)
6x^2+3x-24x-12=9-6x
6x^2-15x-21=0
x= 3.5 or-1

7.5x(x-2)=(x-2)^2
5x^2-10x=x^2-4x+4
4x^2-6x-4=0
x=2 or-0.5

8.3y(y-6)=y^2-36
3y^2-18y=y^2-36
2y^2-18y+36=0
y=6 or 3

9.(2x-5)^2=(x-3)(2x-5)
4x^2-20x+25=2x^2-5x-6x+15
2x^2-9x+10=0
x=2.5 or 2

10.(x+1)^2+3(x+1)-4=0
x^2+2x+1+3x+3-4=0
x^2+5x=0
x=0 or -5

2009-01-07 18:39:11 補充:
all the questions i use quartratic equation (ax^2+bx+c=0)to solve.

1+2/3=一又二分之三
2009-01-08 4:10 am
1.(x+3)(2x+1)+3=0
[x(2x+1)+3(2x+1)]+3=0
(2x²+x+6x+3)+3=0
2x²+x+6x+3+3=0
2x²+7x+6=0
2x²+7x=- 6
x(2x+7)=- 6
2x+7=- 6/x
2x=(- 6-7x)/x
2=- 6-7x
8=- 7x
8/-7=x
x=8/-7

2.(3x+1)(1-2x)+4=0
3x(1-2x)+1(1-2x)+4=0
3x-6x²+1-2x+4=0
x-6x²+5=0
x-6x²=- 5
x(1-6x)=- 5
1-6x=- 5/x
[x(1-6x)]/x=-5/x
5x=1-6x
11x=1
x=1/11

3.x^2-3x(x-5)=25
x²-3x²+15x=25
-2x²+15x=25
x(-2x+15)=25
-2x+15=25/x
-2x=(25-15x)/x
-2x/x=(25-15x)/x
0=25-15x
-25=-15x
x=5/3

4.2y(19-4y)=35
19- 4y=35/2y
- 4y=(35-38y)/2y
-2=35-38y
38y=37
y=37/38

5.15(y^2+1)=34y
SORRY= I CANNOT CALCALATE

6.(x-4)(6x+3)=3(3-2x)
x(6x+3)- 4(6x+3)=9-6x
6x²+3x-24x-12=9-6x
6x²-21x-12=9-6x
6x²-27x=21
3x(2x-9)=21
2x-9=21/3x
2x-9=7/x
2=7+9x
-5=9x
x=-5/9

7.5x(x-2)=(x-2)^2
5x²-10x=(x)²+(2)²-2(x)(2)
5x²-10x=x²+4- 4x
4x²- 6x=4
2x(2x-3)=4
2x-3=4/2x
2x=(2+3x)/x
2=2+3x
x=-3

8.3y(y-6)=y^2-36
3y²-18y=y²-36
2y²-18y=-36
2y(y-9)=36
y-9=36/2y
-18=9y
y=-2

9.(2x-5)^2=(x-3)(2x-5)
(2x)²+(5)²-2(2x)(5)=x(2x-5)-3(2x-5)
4x²+25-20x=2x²-5x-6x+15
2x²-9x=-10
x(2x-9)=-10
2x-9=-10/x
2x=(-10+9x)/x
2=-10+9x
12=9x
x=4/3

10.(x+1)^2+3(x+1)-4=0
(x)²+(1)²+2(x)(1)+3x+3- 4=0
x²+1+2x+3x-1=0
x²+5x=0
x(x+5)=0
x+5=0
x=-5

P.S.我只係一個中二學生,如果我計o個D答案係錯ge 話,請告訴我,THX!!!
2009-01-08 4:01 am
1. 解 : (2x²+7x+3)+3=0
2x²+7x+6=0
2x²+4x+3x+6=0
(2x+3)(x+2)=0
x=-3/2 x=-2

2. 解 : (3x+1-6x²-2x)+4=0
-6x²+x+5=0
6x²-x-5=0
6x²+5x-6x-5=0
(6x+5)(x-1)=0
x=1 x= -5/6

3. 解 : x²-3x²+15x-25=0
-x²+15x-25=0
x²-15x+25=0


4. 解 : 38y-8y²-35=0
8y²-38y+35=0
8y²-10y-28y+35=0
(4y-5)(2y-7)=0
y=5/4 y=7/2


5. 解 : 15y²+15=34y
15y²-34y +15=0
15y²-9y-25y+15=0
(5y-3)(3y-5)=0
y=3/5 y=5/3


6. 解 : 6x²-24x+3x-12=9-6x
6x²-15x-21=0
2x²-5x-7=0
2x²-7x+2x-7=0
(2x-7)(x+1)=0
x=7/2 x=-1



7. 解 : 5x=x-2
4x=-2
2x=-1
x=-1/2
x-2=0
x=2


8. 解 : 3y²-18y=y²-36
2y²-18y+36=0
y²-9y+18=0
(y-6)(y-3)=0
y=6 y=3


9. 解 : 2x-5=0
x=5/2
2x-5=x-3
x-2=0
x=2


10. 解 : x²+2x+1+3x+3-4=0
x²+5x+0=0
x=0

2009-01-07 20:02:22 補充:
第3題暫時還未計到


收錄日期: 2021-04-13 16:21:12
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