please solve by substitution?

7x - 9y = 1
y = 5x -17

Substitute y with 5x - 17 in the first equation.
7x - 9y = 1
7x - 9(5x -17) = 1

Distribute.
7x - 9(5x) - 9(-17) = 1
7x - 45x + 153 = 1
-38x + 153 = 1

Subtract 153 from both sides.
-38x + 153 - 153 = 1 - 153
-38x = -152

Divide both sides by -38.
-38x / -38 = -152 / -38
x = 4

Plug this into the second equation to find y.
y = 5x -17
y = 5(4) -17
y = 20 - 17
y = 3

ANSWER: (4, 3)

CHECK:
7x - 9y = 1
7(4) - 9(3) = 1?
28 - 27 = 1?
1 = 1?
TRUE

y = 5x -17
3 = 5(4) - 17?
3 = 20 - 17?
3 = 3?
TRUE

7x - 9y = 1
y = 5x - 17

7x - 9y = 1
7x - 9(5x - 17) = 1
7x - 45x + 153 = 1
-38x = 1 - 153
-38x = -152
x = -152/-38
x = 4

y = 5x - 17
y = 5(4) - 17
y = 20 - 17
y = 3

∴ x = 4 , y = 3

7x-9(5x-17)=1
7x-45x+153=1
152=38x
152/38=x
4=x.

y=20-17
y=3

28-27=1

7x - 9 (5x - 17) = 1
7x - 45x + 153 = 1
152 = 38x
x = 152 / 38
x = 4

real easy,

1) 7x - 9y = 1
2) y = 5x -17

1) x9 = 3) 9y= 15x-153

7x - 15x-153 = 1
8x=152
x=19

5*19 - 17 = y

y= 95 - 17

y=78
x=19


i think that's right :S, should be i did it the other week at school